Помогите, пожалуйста, вычислить интеграл
int (0 (pi)^(1/2)) y * sin y^2 dy
int (0 (pi)^(1/2)) y * sin y^2 dy = int (0 (pi)^(1/2)) sin y^2 d(1/2 * y^2) =
= 1/2 * int (0 (pi)^(1/2)) sin y^2 d(y^2) = | y^2 = t | = 1/2 * int (0 pi) sin t dt =
= 1/2 * (-cos t)_{0}^{pi} = 1/2 * (-cos pi + cos 0) = 1/2 * (1 + 1) = 1
Спасибо.
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