Здравствуйте, помогите начать решение:
Нужно составить уравнение траектории точки, заданы координаты
x=12sin(Пt/6)
y=2t^2+2
надо исключить время из заданных уравнений движения, но как?
t=sqrt(у-2/2)
x=12sin((П/6)*sqrt(у-2/2))
Кривая получается синусоида
Правильно?
Я бы скобочек добавил.
x=12sin((П/6)*sqrt((у-2)/2))
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