y''*y*y*y - 3 = 0
kak reshit?
Esli,
y'=z, z=z(y), y''=z*z'
resenie:
y*y*y*z*z' - 3 = 0 / :z
y*y*y*z'-3/z=0
y*y*y*dz/dy-3/z=0 /*dy
y*y*y*dz-(3/z)*dy=0 /*z :y*y*y
z*dz=(3/y*y*y)*dy=0
tak pravilno?
Dalee u menya poluchaetsya
z*z*y*y+3=C1
z*z=-3/y*y+C1/y*y
I esli moi vichisleniya verni
To kakoi otvet okonchatelnii, esli net nachalnih usloviy?