1) int(6;6sqrt(3)) [dx\(x)^2+36] = int(6;6sgrt(3)) [dx\(x)^2 +(6)^2]= int(6;6sqrt(3)) [1\6 arctg(x\6)]= 1\6 (arct[6\6] - arctg[6sqrt(3)\6] = 1\6 (pi\4 - pi\3)

2)int(0;pi) [(pi - x) sin(x) dx] = int(0;pi) [-(pi - x)cos x ]|(0;pi) - int(0;pi)[ -cos(x) (-dx)] = -(pi-pi) cos(pi) - int(0;pi) [cos(x) dx] = 1 - int(0;pi) sin(x) dx = 1- (sin(pi)-sin(0)) = 1

3) int(1;4) [dx\(x)^2-2x+10] = int(1;4)[ dx\(x-1)^2 +3^2] = int(0;3)[ dx\t^2 +3^2] = 1\3 arctg(t\3) |(0;3)= 1\3 (arctg(1) - arctg(0)) = pi\12
Большое спасибо