Цитата(cepreu @ 21.3.2009, 17:21) *

int (4+4cos(2t))/2dt=int 2(2cos(2t))dt=2 int(1+cos(2t))dt=2int dt [0;pi/2] + 2 int cos(2t)dt = pi + 2 sin(2t)/2 [0;pi/2] = pi


Да

2 пропустили
int (4+4cos(2t))/2dt=int (2+2cos(2t))dt= дальше верно