Цитата
f(x) = f(-1) + f'(-1)/1! * (x + 1) + f''(-1)/2! * (x + 1)^2 + f'''(-1)/3! * (x + 1)^3 + ...
f(x)=x^4+x^-3x^2+5
f'(x)=4x^3+3x^2-6x
f''(x)=12x^2+6x-6
f'''(x)=24x+6
f''''(x)=24
f(-1)=2
f'(-1)=5
f''(-1)=0
f'''(-1)=-18
f''''(-1)=24
f(x)=2-5(x+1) - 18/6(x+1)^3+24/24(x+1)^4
f(x)=(x+1)^4-3(x+1)^3-5(x+1)+2
так?