int (1 2) dx/(x - 1)^2 = lim (a -> 1+0) int (a 2) dx/(x - 1)^2 =
= lim (a -> 1+0) (-1/(x - 1))_{a}^{2} = lim (a -> 1+0) (-1/(2 - 1) + 1/(a - 1)) =
= lim (a -> 1+0) (-1 + 1/(a - 1)) = +00 => интеграл расходится