Цитата(luludu @ 16.9.2008, 20:48) *

m+n=(m^(1/3)+n^(1/3))(m^(2/3)-(n*m)^(1/3)+n^(2/3))
может так?

Опечатался.

m+n=(m^(1/3)+n^(1/3))(m^(2/3)-(m*n)^(1/3)+n^(2/3))