int (-3 2) dx/(x + 3)^2 = | x + 3 = t, x = t - 3, dx = dt | =
= int (0 5) dt/t^2 = lim (a->0) int (a 5) dt/t^2 = lim (a->0) (-1/t)_{a}^{5} =
= lim (a->0) (-1/5 + 1/a) = 00 => интеграл расходится