Цитата(Metalmih @ 12.5.2010, 18:01) *

Получил так:
Lim(x->00) (2x^4+2x^2+5x-6)/(x^3+2x^2+7x-1)=
=Lim(x->00)(x^4(2+2/x^2+5/x^3+6/x^4))/(x^3(1+2/x^3+7/x^3+1/x^4)=
=Lim(x->00)(x(2+2/x^2+5/x^3-6/x^4)/(1+2/x^3+7/x^3-1/x^4)=
=Lim(x->00)(x(2+0+0-0))/(1+0+0-0)=
=Lim(x->00)2x/1=[2/0]=2/00=00

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