и значит ∫ z^3 +1 /(z +2)^2 (z- 3) dz =2Пi (res z1 F(z)) m=2
|z|=5/2

res z1 F(z) = 1/m -1! lim(z-> z1)(F(z)(z-z1)^m)^m -1) = 1/2-1! lim z-> -2
(z^3 +1 /(z +2)^2 (z- 3) * (z+2)^2)^(2-1)) = lim z-> -2(z^3 +1/(z- 3)` =
lim z ->-2 (3z^2 -z^3 -1/ (z -3)^2 = 19/25
следователньо
∫ z^3 +1 /(z +2)^2 (z- 3) dz =2Пi (19/25)
|z|=5/2
Верно?